2412af…: “Against a beautiful quadrilateral”

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1 : Consider the function $f:\mathbb {R}\rightarrow \mathbb {R}$ defined by $f(x) = \sage {p1f1}$ . The name of the function is $\answer {f}$ .

Remember that the function is named before the colon when the function’s domain and codomain are given.

1.1 : What is the rule that defines $f(x)$ ? $x$ is mapped to $\answer {\sage {p1f1}}$ .

Remember that the rule to define $f(x)$ is the function equation that is given after the “ $=$ ” sign and containing the $x$ .

1.1.1 : $f(\sage {p1c4}) = \answer {\sage {p1ans1}}$ .

Remember that the notation $f(x)$ is denoting the $x$ as the placeholder for the input; so $f(\sage {p1c4})$ means you should substitute $\sage {p1c4}$ wherever there is an $x$ in the rule for $f(x)$ .

2 : Consider the function $f:\mathbb {R}\rightarrow \mathbb {R}$ defined by $f(x) = \sage {p2f1}$ . The name of the function is $\answer {f}$ .

Remember that the function is named before the colon when the function’s domain and codomain are given.

2.1 : What is the rule that defines $f(x)$ ? $x$ is mapped to $\answer {\sage {p2f1}}$ .

Remember that the rule to define $f(x)$ is the function equation that is given after the “ $=$ ” sign and containing the $x$ .

2.1.1 : $f(\sage {p2c4}) = \answer {\sage {p2ans1}}$ .

Remember that the notation $f(x)$ is denoting the $x$ as the placeholder for the input; so $f(\sage {p2c4})$ means you should substitute $\sage {p2c4}$ wherever there is an $x$ in the rule for $f(x)$ .

3 : Consider the function $f:\mathbb {R}\rightarrow \mathbb {R}$ defined by $f(x) = \sage {p3f1}$ . The name of the function is $\answer {f}$ .

Remember that the function is named before the colon when the function’s domain and codomain are given.

3.1 : What is the rule that defines $f(x)$ ? $x$ is mapped to $\answer {\sage {p3f1}}$ .

Remember that the rule to define $f(x)$ is the function equation that is given after the “ $=$ ” sign and containing the $x$ .

3.1.1 : $f(\sage {p3c4}) = \answer {\sage {p3ans1}}$ .

Remember that the notation $f(x)$ is denoting the $x$ as the placeholder for the input; so $f(\sage {p3c4})$ means you should substitute $\sage {p3c4}$ wherever there is an $x$ in the rule for $f(x)$ .