1a2dba…: “Besides the purple cube”

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Note: This is using an experimental factoring validator. If you verified that your answer should be correct and Xronos won’t take it, please email your instructor to see if there is a problem.

1 : Factor the following quadratic using the AC-Method. $p(x) = \sage {p1f3} = \answer [validator=factorCheck]{\sage {p1ans}}$

Remember to multiply the A term and the B term and try to find values that multiple to that new value ( $\sage {p1c1*p1c2*p1c3*p1c4}$ ), but add to $\sage {p1c3*p1c2+p1c1*p1c4}$ . Use those to numbers to split the middle term and then factor by grouping (as shown in the video).

2 : Factor the following quadratic using the AC-Method $p(x) = \sage {p2f3} = \answer [validator=factorCheck]{\sage {p2ans}}$

Remember to multiply the A term and the B term and try to find values that multiple to that new value ( $\sage {p2c1*p2c2*p2c3*p2c4}$ ), but add to $\sage {p2c3*p2c2+p2c1*p2c4}$ . Use those to numbers to split the middle term and then factor by grouping (as shown in the video).

3 : Factor the following quadratic using the AC-Method $p(x) = \sage {p3f3} = \answer [validator=factorCheck]{\sage {p3ans}}$

Remember to multiply the A term and the B term and try to find values that multiple to that new value ( $\sage {p3c1*p3c2*p3c3*p3c4}$ ), but add to $\sage {p3c3*p3c2+p3c1*p3c4}$ . Use those to numbers to split the middle term and then factor by grouping (as shown in the video).

4 : Factor the following quadratic using the AC-Method $p(x) = \sage {p4f3} = \answer [validator=factorCheck]{\sage {p4ans}}$

Remember to multiply the A term and the B term and try to find values that multiple to that new value ( $\sage {p4c1*p4c2*p4c3*p4c4}$ ), but add to $\sage {p4c3*p4c2+p4c1*p4c4}$ . Use those to numbers to split the middle term and then factor by grouping (as shown in the video).