You want to factor by grouping, so you want to group up terms into pairs and then factor out any common terms from each pair. For example, if you had $9x^3 + 8x^2 - 144x - 128$ then you could group it as $(9x^3+8x^2) + (-144x -128)$, then factor out any common factors in each group; $x^2(9x+8) + -16(9x+8)$, then pull out the common term in the parentheses (only works if they are the same!) to get $(9x+8)(x^2-16)$. This isn’t the end though; you need to fully factor, so you need to check both terms to see if either is factorable, in this case $(x^2-16)$ is factorable to $(x-4)(x+4)$ which gets you $(9x+8)(x-4)(x+4)$ as your final factoring.

You want to factor by grouping, so you want to group up terms into pairs and then factor out any common terms from each pair. For example, if you had $9x^3 + 8x^2 - 144x - 128$ then you could group it as $(9x^3+8x^2) + (-144x -128)$, then factor out any common factors in each group; $x^2(9x+8) + -16(9x+8)$, then pull out the common term in the parentheses (only works if they are the same!) to get $(9x+8)(x^2-16)$. This isn’t the end though; you need to fully factor, so you need to check both terms to see if either is factorable, in this case $(x^2-16)$ is factorable to $(x-4)(x+4)$ which gets you $(9x+8)(x-4)(x+4)$ as your final factoring.

You want to factor by grouping, so you want to group up terms into pairs and then factor out any common terms from each pair. For example, if you had $9x^3 + 8x^2 - 144x - 128$ then you could group it as $(9x^3+8x^2) + (-144x -128)$, then factor out any common factors in each group; $x^2(9x+8) + -16(9x+8)$, then pull out the common term in the parentheses (only works if they are the same!) to get $(9x+8)(x^2-16)$. This isn’t the end though; you need to fully factor, so you need to check both terms to see if either is factorable, in this case $(x^2-16)$ is factorable to $(x-4)(x+4)$ which gets you $(9x+8)(x-4)(x+4)$ as your final factoring.

You want to factor by grouping, so you want to group up terms into pairs and then factor out any common terms from each pair. For example, if you had $9x^3 + 8x^2 - 144x - 128$ then you could group it as $(9x^3+8x^2) + (-144x -128)$, then factor out any common factors in each group; $x^2(9x+8) + -16(9x+8)$, then pull out the common term in the parentheses (only works if they are the same!) to get $(9x+8)(x^2-16)$. This isn’t the end though; you need to fully factor, so you need to check both terms to see if either is factorable, in this case $(x^2-16)$ is factorable to $(x-4)(x+4)$ which gets you $(9x+8)(x-4)(x+4)$ as your final factoring.

You want to factor by grouping, so you want to group up terms into pairs and then factor out any common terms from each pair. For example, if you had $9x^3 + 8x^2 - 144x - 128$ then you could group it as $(9x^3+8x^2) + (-144x -128)$, then factor out any common factors in each group; $x^2(9x+8) + -16(9x+8)$, then pull out the common term in the parentheses (only works if they are the same!) to get $(9x+8)(x^2-16)$. This isn’t the end though; you need to fully factor, so you need to check both terms to see if either is factorable, in this case $(x^2-16)$ is factorable to $(x-4)(x+4)$ which gets you $(9x+8)(x-4)(x+4)$ as your final factoring.