bc3e01…: “Before the happy tree”

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1 : Consider the function $f:\{ x \in \mathbb {R} : \sage {p1var1} \} \longrightarrow \{ x \in \mathbb {R} : \sage {p1var2} \}$

What is the domain of the function $f$ ?

$\{ x \in \mathbb {R} : \sage {p1ans1} \}$ $\{ x \in \mathbb {R} : \sage {p1ans2} \}$ $\{ x \in \mathbb {R} : \sage {p1ans3} \}$ $\{ x \in \mathbb {R} : \sage {p1ans4} \}$

Remember that the domain is the “input” of the function, and is the part listed first. So a function $f:A\rightarrow B$ would have a domain of “ $A$ ”.

What is the codomain of the function $f$ ?

$\{ x \in \mathbb {R} : \sage {p1ans1} \}$ $\{ x \in \mathbb {R} : \sage {p1ans2} \}$ $\{ x \in \mathbb {R} : \sage {p1ans3} \}$ $\{ x \in \mathbb {R} : \sage {p1ans4} \}$

Remember that the codomain is the “type of output” of the function, and is the part listed second. So a function $f:A\rightarrow B$ would have a codomain of “ $B$ ”.

2 : Consider the function $f:\{ x \in \mathbb {R} : \sage {p2var1} \} \longrightarrow \{ x \in \mathbb {R} : \sage {p2var2} \}$

What is the domain of the function $f$ ?

$\{ x \in \mathbb {R} : \sage {p2ans1} \}$ $\{ x \in \mathbb {R} : \sage {p2ans2} \}$ $\{ x \in \mathbb {R} : \sage {p2ans3} \}$ $\{ x \in \mathbb {R} : \sage {p2ans4} \}$

Remember that the domain is the “input” of the function, and is the part listed first. So a function $f:A\rightarrow B$ would have a domain of “ $A$ ”.

What is the codomain of the function $f$ ?

$\{ x \in \mathbb {R} : \sage {p2ans1} \}$ $\{ x \in \mathbb {R} : \sage {p2ans2} \}$ $\{ x \in \mathbb {R} : \sage {p2ans3} \}$ $\{ x \in \mathbb {R} : \sage {p2ans4} \}$

Remember that the codomain is the “type of output” of the function, and is the part listed second. So a function $f:A\rightarrow B$ would have a codomain of “ $B$ ”.

3 : Consider the function $f:\{ x \in \mathbb {R} : \sage {p3var1} \} \longrightarrow \{ x \in \mathbb {R} : \sage {p3var2} \}$

What is the domain of the function $f$ ?

$\{ x \in \mathbb {R} : \sage {p3ans1} \}$ $\{ x \in \mathbb {R} : \sage {p3ans2} \}$ $\{ x \in \mathbb {R} : \sage {p3ans3} \}$ $\{ x \in \mathbb {R} : \sage {p3ans4} \}$

Remember that the domain is the “input” of the function, and is the part listed first. So a function $f:A\rightarrow B$ would have a domain of “ $A$ ”.

What is the codomain of the function $f$ ?

$\{ x \in \mathbb {R} : \sage {p3ans1} \}$ $\{ x \in \mathbb {R} : \sage {p3ans2} \}$ $\{ x \in \mathbb {R} : \sage {p3ans3} \}$ $\{ x \in \mathbb {R} : \sage {p3ans4} \}$

Remember that the codomain is the “type of output” of the function, and is the part listed second. So a function $f:A\rightarrow B$ would have a codomain of “ $B$ ”.

4 : Consider the function $f:\{ x \in \mathbb {R} : \sage {p4var1} \} \longrightarrow \{ x \in \mathbb {R} : \sage {p4var2} \}$

What is the domain of the function $f$ ?

$\{ x \in \mathbb {R} : \sage {p4ans1} \}$ $\{ x \in \mathbb {R} : \sage {p4ans2} \}$ $\{ x \in \mathbb {R} : \sage {p4ans3} \}$ $\{ x \in \mathbb {R} : \sage {p4ans4} \}$

Remember that the domain is the “input” of the function, and is the part listed first. So a function $f:A\rightarrow B$ would have a domain of “ $A$ ”.

What is the codomain of the function $f$ ?

$\{ x \in \mathbb {R} : \sage {p4ans1} \}$ $\{ x \in \mathbb {R} : \sage {p4ans2} \}$ $\{ x \in \mathbb {R} : \sage {p4ans3} \}$ $\{ x \in \mathbb {R} : \sage {p4ans4} \}$

Remember that the codomain is the “type of output” of the function, and is the part listed second. So a function $f:A\rightarrow B$ would have a codomain of “ $B$ ”.