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Mathematical Expression Editor
We explore functions that “shoot to infinity” near certain points.
Video Lecture
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Consider the function
While the does not exist, we learned in the last section that we can still say something about the behavior of the
function.
Which of the following are correct?
, so , so as ,
The right arrow “” means “goes to” or “approaches”. Remember that this is essentially what the limit is already saying; so
saying is a little redundant. Indeed this would be translated to say “as x goes to -1, the function goes to ’goes
to infinity’.” Which isn’t quite right. So if you use the “” notation, then you should use an equals sign. If you
don’t, then you should use the “” to signify that the function is approaching a value, but not “equal” to a value.
On the other hand, consider the function
While the two sides of the limit as approaches do not agree, we can still consider the one-sided limits. We see and
.
If at least one of the following hold:
,
,
,
then the line is a vertical asymptote of .
Find the vertical asymptotes of
Since is a rational function, it is continuous on its domain. So the only points where the function can possibly have a vertical
asymptote are zeros of the denominator. Start by factoring both the numerator and the denominator: Using limits, we must investigate what happens with when and , since and are
the only zeros of the denominator. Write
Now write
Consider the one-sided limits separately.
When , the quantity is positive and approaches and the numerator is negative, therefore, .
On the other hand, when , the quantity is negative and approaches and the numerator is negative, therefore,
.