0fba3c…: “Back to a lime parallelogram”

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Solve for $x$ in the following logarithmic equation: $\log _{\sage {p1b1}}\left (\sage {p1f1}\right ) = \sage {p1c3}$

$x = \answer {\sage {p1ans1}}$ .

Solve for $x$ in the following logarithmic equation: $\log _{\sage {p2b1}}\left (\sage {p2f1}\right ) = \sage {p2c3}$

$x = \answer {\sage {p2ans1}}$ .

Solve for $x$ in the following logarithmic equation: $\log _{\sage {p3b1}}\left (\sage {p3f1}\right ) = \sage {p3c3}$

$x = \answer {\sage {p3ans1}}$ .

Solve for $x$ in the following logarithmic equation: $\log _{\sage {p4b1}}\left (\sage {p4f1}\right ) = \sage {p4c3}$

$x = \answer {\sage {p4ans1}}$ .