Absolute Value: Analytic View Practice 1

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This gives practice for understanding the absolute value analytically.

1 : Consider the following absolute value expression: $|\sage {p1f1}| + \sage {p1f2}$

Fill in the missing pieces of the following piecewise definition

$|\sage {p1f1}| + \sage {p1f2} = \begin {cases} \answer {\sage {p1ans1}} & x < \answer {\sage {p1ans3}} \\ \answer {\sage {p1ans2}} & x \geq \answer {\sage {p1ans3}} \end {cases}$

2 : Consider the following absolute value expression: $|\sage {p2f1}| + \sage {p2f2}$

Fill in the missing pieces of the following piecewise definition

$|\sage {p2f1}| + \sage {p2f2} = \begin {cases} \answer {\sage {p2ans1}} & x < \answer {\sage {p2ans3}} \\ \answer {\sage {p2ans2}} & x \geq \answer {\sage {p2ans3}} \end {cases}$

3 : Consider the following absolute value expression: $|\sage {p3f1}| + \sage {p3f2}$

Fill in the missing pieces of the following piecewise definition

$|\sage {p3f1}| + \sage {p3f2} = \begin {cases} \answer {\sage {p3ans1}} & x < \answer {\sage {p3ans3}} \\ \answer {\sage {p3ans2}} & x \geq \answer {\sage {p3ans3}} \end {cases}$

4 : Consider the following absolute value expression: $|\sage {p4f1}| + \sage {p4f2}$

Fill in the missing pieces of the following piecewise definition

$|\sage {p4f1}| + \sage {p4f2} = \begin {cases} \answer {\sage {p4ans1}} & x < \answer {\sage {p4ans3}} \\ \answer {\sage {p4ans2}} & x \geq \answer {\sage {p4ans3}} \end {cases}$